program mnojecvo;
const
n=1;
var
a,b,c,d,e: set of 1..200;
j,x,y: byte;
begin
a:=[];
b:=[3,5,8];
d:=[1,3,6];
e:=[1,3,8];
for j:=1 to 5 do
begin
readln(x);
a:=a+[x]
end;
c:=a-b-d-e;
for x:=1 to 200 do
if(x in c) then writeln(x);
readln;
end.